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7 Determine the length of the line segment N in Fig 7-7 Using a calculator, approximate the answer by rounding off to three decimal places 8 Determine the coordinates of the midpoint of line segment L in Fig 7-7 9 Determine the coordinates of the midpoint of line segment M in Fig 7-7 10 Determine the coordinates of the midpoint of line segment N in Fig 7-7

Time estimates are more accurate if the person who will do the work creates them at a detailed level. But suppose you approach Joe, the engineer or a programmer who will be working with you, and he says, I m sorry. I m not due to start design for another two months. And I just don t have the time right now. How do you convince him to take a few hours now to prevent problems later First of all, make it as easy as possible. O er either to work with him, or to provide him with templates with clear instructions. (Some people prefer one; others prefer the other.) Secondly, engage in a conversation about his own past experience. For example, ask, What did you like least about working on projects in the past Joe might say, Being given two weeks for a job that I know takes four.

We ve learned how to work with Cartesian coordinates in two and three dimensions, and we ve learned about vectors in two dimensions Now it s time to explore how vectors behave in Cartesian xyz space

Imagine two vectors a and b in three-dimensional space We have infinitely many more direction possibilities now than we did in two-space! We can denote our vectors as arrowed line segments, starting at the origin (0,0,0) and ending at points (xa,ya,za) and (xb,yb,zb), as shown in Fig 8-1

Cartesian standard form In Cartesian xyz space, vectors don t have to start at the coordinate origin, but there are advantages to putting them in that form Any vector in this coordinate system, no matter where it starts and ends, has an equivalent vector whose originating point is at (0,0,0) Such a vector is in Cartesian standard form Suppose that we have a vector a that starts at a point P1 and ends at another point P2, with coordinates as

You reply, Joe, this is your chance to prevent that from happening this time. If I make the estimate, I ll probably get it wrong. But if you take just a couple of hours right now to clue me in, then you ll estimate the time yourself. Tell me now that it s going to take three weeks, and I ll get you the three weeks you need. Make a strong e ort to do this whenever you can. It will give you more accurate estimates and a better understanding of the project. More importantly, it will give each team member control over his or her own work. People are much more productive when they are in charge of the design of their own tasks and estimate and de ne their own work schedule.

P1 = (x1,y1,z1) and P2 = (x2,y2,z2) as shown in Fig 8-2 The standard form of a , denoted a, is defined by the terminating point Pa such that Pa = (xa,ya,za) = [(x2 x1),(y2 y1),(z2 z1)]

To find the time constant, the differential equation must be reduced to its standard form: 2gC2A2 Ap = pFThe time constant is then the coefficient of dF/dt: r2LAC2 F (3.1)

a (xa, ya, za)

b (xb, yb, zb)

As project manager, you will be coordinating all of this communication and building the project plan and requirements speci cation. On large projects, you will focus on the plan, and assign the speci cation work to your team.

drawing (as are all three-space renditions in this book) In real life, both vectors in this particular case would project generally toward us

+y Pa (xa, ya, za)

Flow coefficient C2 can be replaced by its steady-state equivalent: